Pairs of Angles

 In the adjoining figure, $ABCD$ is a parallelogram in which $\angle BAO=35°,\angle DAO=40°$ and $\angle COD=105°.$ If $\angle ABO=k°$, then find the value of $k$.

In the adjacent figure, it is given that, $\mathrm{BC}\parallel \mathrm{DE}, \angle \mathrm{BAC}=35° \mathrm{and} \angle \mathrm{BCE}=102°$. If the measure of $\angle \mathrm{BCA}=k°$, find $k$.

In the figure, the value of $x$ is